If 230 volts is applied to a 160 turn primary winding, what is the voltage in the 320 secondary winding of the transformer?

To determine the voltage in the secondary winding of a transformer, one can use the transformer turns ratio formula, which is based on the principle of electromagnetic induction. The ratio of the primary voltage to the secondary voltage is equal to the ratio of the number of turns in the primary winding to the number of turns in the secondary winding. This can be articulated as:

[ \frac{V_p}{V_s} = \frac{N_p}{N_s} ]

Where:

• ( V_p ) is the primary voltage

• ( V_s ) is the secondary voltage

• ( N_p ) is the number of turns in the primary winding

• ( N_s ) is the number of turns in the secondary winding

In this scenario:

• The primary voltage ( V_p ) is 230 volts

• The primary turns ( N_p ) is 160 turns

• The secondary turns ( N_s ) is 320 turns

Substituting the known values into the formula gives:

[ \frac{230}{V_s} = \frac{160}{320} ]

This simplifies to:

[ \frac{230}{V_s} = \frac{1}{2} ]

Cross-m